See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Let the equation of other asymptote is x y 0   , tangent meet both the asymptote at     A 0,2 and B 0, mid of both the point is P Hence 0  Now area of triangle ABP is 0 0 1 1 0 2 1 1 2 1 1 1   , hence latus rectum is 2.