Number of electrons present in 4f orbital of Ho ion is __________ (Given Atomic No. of Ho = 67) 3+ — d and f Block Elements Chemistry Question

💡 Solution & Explanation

**Step 1: Write the electron configuration of neutral Ho** Holmium (Ho) has atomic number 67. Electron configuration: [Xe] 4f¹¹ 5d¹ 6s² Total electrons = 67 **Step 2: Determine the electron configuration of Ho³⁺ ion** Ho³⁺ means the ion has lost 3 electrons. Electrons removed from the outermost orbitals first: 6s² and 5d¹ Ho³⁺ configuration: [Xe] 4f¹⁰ **Step 3: Identify electrons in the 4f orbital** From the Ho³⁺ configuration [Xe] 4f¹⁰, the 4f orbital contains 10 electrons. **Therefore, the answer is 10.00.**