A quantity of 1.9 * 10^-4 g of metal (density 19 g/ml) is dispersed in 1 L of water to give spherica — Surface Chemistry Chemistry Question
Question
A quantity of 1.9 * 10^-4 g of metal (density 19 g/ml) is dispersed in 1 L of water to give spherical particles of radius 10 nm. The number of sol particles per cm3 of the sol is
Answer: A
💡 Solution & Explanation
Volume of 1 particle = (4/3)*π*(10^-6)^3 = 4.189 * 10^-18 cm3. Mass = Vol * d = 7.959 * 10^-17 g. Particles in 1 L = (1.9 * 10^-4) / (7.959 * 10^-17) = 2.387 * 10^12. Particles per cm3 = 2.387 * 10^9.
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