The concentration of acetate ions in 1 M acetic acid (Ka = 2 * 10^-5) solution containing 0.1 M - is — Ionic Equilibrium Chemistry Question
Question
The concentration of acetate ions in 1 M acetic acid (Ka = 2 * 10^-5) solution containing 0.1 M - $HCl$ is
Answer: C
💡 Solution & Explanation
Due to common ion effect from $HCl$, [H+] = 0.1 M. Ka = [CH3COO-][H+] / [CH3COOH]. 2 * 10^-5 = [CH3COO-] * 0.1 / 1. [CH3COO-] = 2 * 10^-4 M.
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