See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

At any time K I B ma x l   ….. (1) q Bv C l  I B Ca l  ….. (2) From (1) and (2) 2 2 k a(B C m) x l   2 2 K a B C m x l        ….. (3) Since motion of connector will be opposite to the displacement from equilibrium. Therefore equation (3) represents S.H.M. 2 2 K B C m l   max 0 V X    max max q B CV  l max 0 q B CX l   0 2 2 KC X m 1 B C l 