Which of the following orbital can not form pi as well as delta-Bond ? — Chemical Bonding Chemistry Question

💡 Solution & Explanation

Step 1: The compound shown is benzyne (C6H4), which is a six-membered carbon ring containing a formal triple bond. Step 2: Four of the carbons in the ring form standard aromatic-type single/double bonds and are sp2-hybridized. The two adjacent carbons forming the formal triple bond are sp-hybridized. Step 3: Therefore, there are 4 sp2-hybridized and 2 sp-hybridized carbon atoms.