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0.023 × 1022 molecules are present in 10g of a substance 'x'. The molarity of a — JEE Mains Chemistry Past Papers Chemistry Question

Question

0.023 × 1022 molecules are present in 10g of a substance 'x'. The molarity of a

Answer: .

💡 Solution & Explanation

Number of mole of X = X of mass Molar 10 . 10 . 23    So molar mass of X = 100g Molarity = M . 2 5   Ans. = 0.025 M M = 25×10–3 So P = 25

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