In an electrochemical reaction of lead. at standard temperature. if E°(pb2+ / pb)=m Volt and E°(Pb4+ — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

Pb2+ + 2e–  Pb 1 E = M ; 1 G  = –2 FM Pb4+ + 4e–  Pb 2 E = N ; 2 G  = –4 FM ________________________________________ Target eq. Pb4+ + 2e–  Pb2+ 3 E = ? ; 3 G  = –2 F 3 E Target eq. = eq. 2 – eq 1 –2F 3 E = –4FN – (–2FM) 3 E = 2N – M = |M – 2N| X = 2 | JEE(Main) 2023 | DATE : 11-04-2023 (SHIFT-1) | PAPER-1 | CHEMISTRY PAGE # 7