When 5.1 g of — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

Moles of NH4HS initially taken = mol . mol / g g .  volume of vessel = 2 NH4HS(s) NH3(g) + H2S(g) t = 0 0.1 mol t =  0.1 (1–0.2) 0.1×0.2 0.1×0.2 partial pressure of each component 300 . 2 . 1 . V nRT P      = 0.246 atm  . ) . ( P P k S H NH P 3     = 6.05×10–2  6 | JEE MAIN-2021 | DATE : 27-08-2021 (SHIFT-2) | PAPER-1 | OFFICAL PAPER | CHEMISTRY PAGE # 11