See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

3 , , sin ,1 3 2 2                 & 3 3 3 sin ,1 8              3 3 sin sin 0, 1 & sin sin 1       3 2 ax bx , x Q f x c 11x, x Q         f(x) is continuous at x = 1, x = 2 & x = 3  ax3 – bx2 = c – 11x must have roots 1, 2 & 3  a = 1, b = 6, c = 6.