See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

2H2O  2H2(g) + O2(g) 2x x 3x = 168 x = 56 ml 2 H V = 2x = 112 ml 2 O V = x = 56 ml 11200 ml of H2 at STP = 1 F 112 ml of H2 at STP = 0.01 F Now 5600 ml of O2 at STP = 1F 56 ml of O2 at STP = 0.01 F Amount of electricity passed = 0.01 F = 0.01  96500 = 965 C We get identical results whether are consider H2 or O2