AITS & Test SerieshardNUMERICAL

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Question

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Answer: 124

💡 Solution & Explanation

4 CH xmL  C2H6 = (100–x) mL     4 2 2 2 CH g 2O g CO g 2H O l xmL 2xmL xmL                 2 6 2 2 2 7 C H g O g 2CO g 3H O l 2 7 100 x 100 x 2 100 x 2                7 212 x 2x x 100 x 100 x 2 100 x 2                AITS-FT-III (Paper-1)-PCM(Sol.)-JEE(Advanced)/2024 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 9 700 7 x 212 2x 100 x x 200 2x 250 2 2 2          x 38 X 76mL 2     contraction due to kOH = VCO2 = x + 2 (100-x) = 200-x= 124 mL

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