See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Meq of CH3COOH = 400  0.01 = 4 Meq of NaOH = 500  0.01 = 5 Meq of excess NaOH = 1 3 1 OH 10 1000          pOH = 3, pH = 11  z = 11  x + z = 3.5 + 11 = 14.5