Consider the following representation based on long form of periodic table. [SEE DIAGRAM] Value of all four quantum number for last electron of element 'X' in their ground state is n = 4, l = 1, m = 1

Question

Consider the following representation based on long form of periodic table.
[SEE DIAGRAM]
Value of all four quantum number for last electron of element 'X' in their 
ground state is n = 4, l = 1, m = 1 and s = -1/2 and spin multiplicity of 
element 'X' in their ground state is 4.

Prashant Kotian · Accepted Answer

Correct answer: D. Step 1: Determine the electronic configurations of beryllium (Be: 1s2 2s2), magnesium (Mg: 1s2 2s2 2p6 3s2), and calcium (Ca: 1s2 2s2 2p6 3s2 3p6 4s2). Step 2: Compare their outermost energy levels. All three elements have two s-electrons in their outermost shells, are classified as alkaline earth metals, and belong to group 2 of the periodic table. Step 3: Beryllium has only 4 electrons total, and its outer energy level (n=2) contains no p-orbitals or p-electrons. Therefore, containing a pair of p-electrons in the outermost energy level is not a shared characteristic.

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