At 27ºC, a — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

 = CRT ) . ( 400   =         M 5 . solute 0.083 × 300 400 × 10–5 = solute M × 0.083 × 300 Msolute = 300 . 10   × 105 =       3 . 10 × 105 = 62250 gram/mole