For the reactions of first, second and third orders, K1 = K2 = K3, where concentrations are expresse — Chemical Kinetics Chemistry Question

💡 Solution & Explanation

K1 has units of s^-1 (independent of conc.). K2 has units of M^-1 s^-1 = L mol^-1 s^-1. If conc. is in mol mL^-1, then unit is mL mol^-1 s^-1. Since 1 L = 10^3 mL, K2_new = 10^3 * K2. K3 has units of M^-2 s^-1 = L^2 mol^-2 s^-1. In mol mL^-1, unit is mL^2 mol^-2 s^-1. Since 1 L^2 = 10^6 mL^2, K3_new = 10^6 * K3. Therefore, to keep relation equal: K1 = K2_new * 10^-3 = K3_new * 10^-6.