See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

The mass of 1 cc of (C2H5)4Pb is = 1  1.66 = 1.66g and this is the amount needed per litre. No. of moles of (C2H5)4Pb needed = 323 66 . 1 = 0.00514 ml 1 mole of (C2H5)4Pb requires 4  (0.00514) = 0.0206 ml of C2H5Cl  Mass of C2H5 Cl = 0.0206  64.5 = 1.33 g