See image — Amines Chemistry Question

💡 Solution & Explanation

Step 1: Identify compound Y. Y has molecular formula C2H7N. Amines of this formula: ethylamine (CH3CH2NH2) fits C2H7N. So Y = CH3CH2NH2 (ethylamine). Step 2: Identify nitrile X. LiAlH4 reduces a nitrile R-CN to a primary amine R-CH2NH2. If Y = CH3CH2NH2, then X = CH3CN (acetonitrile), because LiAlH4 reduces CH3CN to CH3CH2NH2. Step 3: Identify Z. X = CH3CN hydrolyzed in acid medium gives a carboxylic acid: CH3CN + H2O (H+) → CH3COOH (acetic acid). So Z = CH3COOH. Step 4: Mixing Y and Z. Y = CH3CH2NH2 (a base) and Z = CH3COOH (an acid). An amine and a carboxylic acid undergo an acid-base reaction to form an ammonium carboxylate salt: CH3COOH + CH3CH2NH2 → CH3COO- + CH3CH2NH3+. This is an ionic salt: (CH3COO-)(CH3CH2NH3+). Step 5: Check options. Option (c) is (CH3COO-)(CH3CH2NH3+), which matches exactly. Why other options fail: - (a) and (b) are amide products, which require heating/dehydration, not simple mixing at room temperature. - (d) has CH3CH2COO- (propanoate) which would come from a different nitrile, and CH3NH2+ which doesn't match ethylamine. Therefore, the correct answer is C.