See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Meqvt. of Fe2+ taken = 50 × 0.16 = 8  Meqvts. of Fe2+ ion left = 3.67 × 0.05 × 6 = 1.10  Meqvts. of Cr+6 in solution = 8 – 1.10 = 6.90  m. mol. of Cr+6 in solution = 6.90/3 = 2.30  m. mol. of Chromite = 2.30/2 = 1.15 Mass of chromite in original sample