JEE Mains Chemistry Past PapershardNUMERICAL

Consider a complex reaction taking place in three steps with rate constants k1, k2 and k3 respectiveJEE Mains Chemistry Past Papers Chemistry Question

Question

Consider a complex reaction taking place in three steps with rate constants k1, k2 and k3 respectively. The overall rate constant k is given by the expression k = 3 k k k . If the activation energies of the three steps are 60, 30 and 10 kJ mol–1 respectively, then the overall energy of activation in kJ mol–1 is __________. (Nearest integer)

Answer: .

💡 Solution & Explanation

RT / Ea – RT / Ea – RT / Ea – RT / Ea – 3 e e e e   RT ) Ea – Ea – Ea ( RT / Ea – 1 e e  –Ea = (Ea2 –Ea1 – Ea3) × 1 Ea = (Ea1 + Ea3 – Ea2) × 1 ) – 60 ( 1 Ea   = 20 kJ

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