The densities of ice and water at 0 °C and 1 bar are 0.96 and 0.99 g/cm³, respectively. If the perce — Solid State Chemistry Question

💡 Solution & Explanation

Volume of a given mass m of ice is V_ice = m / 0.96. Actual volume occupied by molecules = (x/100) × V_ice = (x/100) × (m/0.96). For the same mass of water, volume is V_water = m / 0.99. Percentage of occupied space in water = (Volume of molecules / V_water) × 100 = (x × 0.99) / 0.96 = 33/32 × x. Thus, the percentage of empty space in water is 100 - 33/32 × x.