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AITS & Test SerieshardNUMERICAL

Question

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Answer: 61.00

💡 Solution & Explanation

Sol. K4[Fe(CN)6] K2O Fe2O3 NO3 CO3 + + + +2 -3 +2 [O] - 2- +4 +5 +3 48 1 12 Total  in oxidation number 48 12 1 61     So ‘n’ factor 61 

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