Arrange the following solutions in order of their increasing boiling points. (i) 10–4 M NaCl (ii) 10–4 M Urea (iii) 10–3 M NaCl (iv) 10–2 M NaCl (A) (ii)

Question

Arrange the following solutions in order of their increasing boiling points. (i) 10–4 M NaCl (ii) 10–4 M Urea (iii) 10–3 M NaCl (iv) 10–2 M NaCl

(A) (ii) < (i) < (iii) < (iv)
(B) (i) < (ii) < (iii) < (iv)
(C) (ii) < (i) (iii) < (iv)
(D) (iv) < (iii) < (i) < (ii)

Prashant Kotian · Accepted Answer

Correct answer: A. (Tb = ikbm) i × conc. 10–4 M NaCl i × conc. = 2 × 10–4 10–4 M Urea i × conc. = 1 × 10–4 10–3 M NaCl i × conc. = 2 × 10–3 10–2 M NaCl i × conc. = 2 × 10–2

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