See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

2 8 0 Ni 3d 4s  n  2   n n 2   2 4 Cr 3d d d    transition because in aq. medium it exists as [Cr(H2O)6]2+ 2 3 3 0 2g g V d t e     4 0 0 Ti Ar 3d 4s  no unpaired electron SECTION – B