A litre of buffer — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

NH3 + NH4Cl 0.1 mole 0.1 mole NH3 + HCl NH4Cl 0.1 mole 0.02 mole 0.1 mole 0.08 mole ––– 0.12 mole pOH = pKb + log ] NH [ ] Cl NH [ 4 = 4.745 + log       . 12 . = 4.745 + log       3 = 4.745 + [0.48 – 0.30] = 4.745 + 0.18 = 4.921 pH = 14 – 4.921 = 9.079