The mass of pure gas to be mixed with 70 g of pure so that the partial pressure of is equal to the partial pressure of , is [12]

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Question

The mass of pure $CH_4$ gas to be mixed with 70 g of pure $CO$ so that the partial pressure of $CO$ is equal to the partial pressure of $CH_4$, is [12]

Prashant Kotian · Accepted Answer

Correct answer: A. For equal partial pressures, the moles of and must be equal [12]. Moles of = 70/28 = 2.5 mol [12]. Moles of must be 2.5 mol [12]. Mass of = 2.5 * 16 = 40 g [12].

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