See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

  3 6 2 A B g 3AB g   1 1 -  3 T n 1 2   1 2 2 1 VD n VD n  2 1 2    = 1/2 2 AB 1 3 2 P 4 3atm 2     3 6 A B 1 4 2 P 1 atm 2      3 3 P 3 K 3 1    3 o rG RT n 3    = - 2500 × 3 × 1.1 = - 8250 J.