Consider the following cases of standard enthalpy of reaction (Hr 0 in kJ mol–1) C2H6(g) + 7 O2(g) 2CO2(g) + 3H2O() Hº1 = – 1550 C(graphite) + O2(g) CO2(g) Hº2 = – 393.5 H2(g) + 1 O2(g) H2O() Hº3 = –

Question

Consider the following cases of standard enthalpy of reaction (Hr 0 in kJ mol–1) C2H6(g) + 7 O2(g) 2CO2(g) + 3H2O() Hº1 = – 1550 C(graphite) + O2(g) CO2(g) Hº2 = – 393.5 H2(g) + 1 O2(g) H2O() Hº3 = – 286 The magnitude of (g) H C o f 2 H is _______ kJ mol–1 (Nearest integer).

Prashant Kotian · Accepted Answer

Correct answer: .. 2C(s) + 3H2(g) C2H6(g), Hfº Hfº = f (H0c,m)R – f (H0c,m)P = 2H20 + 2H30 – 2H10 = 95 kJ/mol | JEE(Main) 2025 | DATE : 22-01-2025 (SHIFT-2) | PAPER-1 | CHEMISTRY PAGE # 9

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