A solution is made by mixing one mole of volatile liquid A with 3 moles of volatile liquid B. The vapour pressure of pure A is 200 mm Hg and that of the solution is 500 mm Hg. The vapour pressure of p

Question

A solution is made by mixing one mole of volatile liquid A with 3 moles of volatile liquid B. The vapour pressure of pure A is 200 mm Hg and that of the solution is 500 mm Hg. The vapour pressure of pure B and the least volatile component of the solution, respectively, are:

(A) 1400 mm Hg, A
(B) 600 mm Hg, B
(C) 1400 mm Hg, B
(D) 600 mm Hg, A

Prashant Kotian · Accepted Answer

Correct answer: D. PT = PAº XA + PBº XB (from Raoult's law for 2 volatile miscible liquids) 500 = 200 × 1 + PBº × 3 2000 = 200 + 3PBº PBº = 600 mm Hg. So, A will be less volatile (since PBº > PAº).

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