See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

CH2CH3 (A) HC CH3 Br No gometrical 3 2 O / 2H/H O HCHO   CHO CH2CH3 isomers (B) (C) (D) (E) Also A and E are identical M. Wt. = 96 + 10 = 106 Number of geometrical isomers = 0 x + y = 106 AITS-FT-VII-(Paper-1)-PCM(Sol.)-JEE(Advanced)/19 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 10 Mathematics PART – III SECTION – A