See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Let the final composition, liquid (10 mole) A = x mole, B = (10 – x) mole Vapour (10 moles), A = 10 – x mole; B = x mole Now, o A A A o B B B Y X P 10 x x 400 Y X x 10 x 100 P       x = 10 3 Now, o o A A B B P X P X P   x 10 x 400 100 10 10      = 200.00