See image — IUPAC and Nomenclature Chemistry Question

💡 Solution & Explanation

Step 1 - Identify the parent structure: The compound contains a benzene ring with an -OH group, making it a phenol. The parent name is 'phenol'. Step 2 - Identify substituents: There is a bromine (Br) substituent and a chlorine (Cl) substituent on the ring, in addition to the -OH group. Step 3 - Assign the principal characteristic group and numbering: In phenol nomenclature, the -OH group is attached to C1 (the reference carbon). The ring is then numbered to give the lowest locants to the substituents. Step 4 - Determine positions: Looking at the structure, Br is on the carbon immediately to the left of the -OH carbon, and Cl is on the carbon immediately to the right of the -OH carbon. If -OH is at C1, numbering clockwise gives Cl at C2 and Br at C6; numbering counterclockwise gives Br at C2 and Cl at C6. Step 5 - Apply lowest locant rule: Both directions give locants {2, 6} for the two substituents, so we apply alphabetical order as a tiebreaker. 'Bromo' comes before 'chloro' alphabetically, so Br should get the lower locant (C2) and Cl gets C6. This corresponds to numbering counterclockwise (Br at C2, Cl at C6). Step 6 - Construct the name: With -OH at C1, Br at C2, and Cl at C6, the IUPAC name is 2-bromo-6-chlorophenol. Therefore, the correct answer is 2-bromo-6-chlorophenol.