See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

AITS-OT-(Paper-2)-PCM(Sol.)-JEE(Advanced)/19 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 7 Sol.   2 2 n a P V nb nRT V          n = 1   2 a P V b RT V          If ‘b’ is negligible, then 2 a P V RT V         , 2 RT a P V V   The equation is quadratic in ‘V’, thus 2 2 RT R T 4aP V 2P     ‘V’ has one value at a given P and T, thus numerical value of discriminant = 0 So, 2 2 R T 4aP      2 2 2 2