See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

(for Q. 27 to Q. 28) (i) The solid must contain Na and I. The yellow colouration of the flame indicates the presence of Na+ ion; a yellow silver salt that is dissolved only by strong complexing agent such as CN or 2 2 3 S O must be AgI. (ii) Reaction (i) to (iv) indicates a sodium salt of an oxygen containing acid containing iodine. Both SO2 and I– are oxidized, while in the first case Iis formed with an intermediate of I2 or 3I(brown solution) and in the second I2 or ( 3I) is formed. As the solution is neutral NaIO3 or NaIO4 come into consideration. (iii) Conditions given in observation(v) proves that solid (x) is NaIO4. 1 mole of NaIO4 = 213.90 g NaIO4 = 8 moles of  2 2 3 S O .        3 2 4 2 3