See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Balmer series 2 2 1 1 1 1 R 2 3          = 5R 36 Lyman series 2 2 2 1 1 1 3R R 4 1 2           2 1 4 5R 20 5 3R 36 108 27       2 1 5 5 27 27      6563 = 1215 Å For More Material Join: @JEEAdvanced_2024 AITS-FT-IX-PCM(Sol.)-JEE(Main)/2023 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 6