A set of solutions is prepared using 180 g of water as a solvent and 10 g of different non-volatile solutes A, B and c. The relative lowering of vapour pressure in the presence of these solutes are in

Question

A set of solutions is prepared using 180 g of water as a solvent and 10 g of different non-volatile solutes A, B and c. The relative lowering of vapour pressure in the presence of these solutes are in the order [Given, molar mass of A = 100 g mol–1; B = 200 g mol–1; C = 10,000 g mol–1]

(A) A > B > C
(B) B > C > A
(C) C > B > A
(D) A > C > B

Prashant Kotian · Accepted Answer

Correct answer: A. Relative lowering in vapour pressure depends on no. of mole of solute greater the no. of mole of solute greater in RLVP and smaller will be vapour pressure. So order of vapour pressure is B > C > A. | JEE MAIN-2020 | DATE : 06-09-2020 (SHIFT-2) | PAPER-1 | OFFICIAL PAPER | CHEMISTRY PAGE # 4

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