See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Average velocity 2 8RT 4 10 M     4 RT 2 M 10     Total kinetic energy of ‘He’ 3 3 6 9RT nRT RT 2 2 4 4      Total kinetic energy of ‘He’ 4 9 2 M 10 4      3 4 9 2 4 10 10 4      180 Joule   Total kinetic energy of 20 3 3 12 'Ne ' nRT RT 2 2 20     For More Material Join: @JEEAdvanced_2025 AITS-OT-II (Paper-2)-PCM(Sol.)-JEE(Advanced)/2025 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 12 4 9 2 M 10 10      3 4 9 2 20 10 10 10      360 Joule   Average kinetic energy of mixture per mole 360 180