The degree of dissociation of water at 25°C is 1.8 * 10^-7% and density is 1.0 g cm^-3. The ionic co — Ionic Equilibrium Chemistry Question

💡 Solution & Explanation

Density of water = 1.0 g/cm^3 = 1000 g/L. The concentration of water [$H_2O$] = 1000 / 18 = 55.56 M. Degree of dissociation α = 1.8 * 10^-7% = 1.8 * 10^-9. Since $H_2O$ dissociates into H+ and OH-, we have [H+] = [OH-] = C * α = 55.56 * 1.8 * 10^-9 = 1.0 * 10^-7 M. The ionic product Kw = [H+][OH-] = (1.0 * 10^-7)^2 = 1.0 * 10^-14.