Correct answer: A,B,D. 3A(g) 2B(g) 2C(g)   t = 0 P0 t = 20 P0 – x 2x 3 2x 3 t  0 0 2P 3 0 2P 3 0 4P 4 3  P0 = 3 atm 0 x P

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Question

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Answer: A,B,D

💡 Solution & Explanation

3A(g) 2B(g) 2C(g)   t = 0 P0 t = 20 P0 – x 2x 3 2x 3 t  0 0 2P 3 0 2P 3 0 4P 4 3  P0 = 3 atm 0 x P

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