See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

For QA + QB to be minimum, using triangle inequality QA QB AB   .  min QA QB AB,   now image of point B in the given plane 7 1 7 B' , , 3 3 3        Now, solving plane with line AB’ we get 7 1 7 Q , , a c 10b 2 5 5 5            For QA QB  is maximum, using triangle inequality we get max QA QB AB   therefore points A, B and Q are collinear, now solving equation of line AB with plane we get   Q 3,3,3 a 2b c 0     . For More Material Join: @JEEAdvanced_2024 AITS-CRT-III (Paper-1)-PCM(Sol.)-JEE(Advanced)/2023 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 10