JEE Mains Chemistry Past PapershardMCQ SINGLE

On heating a mixture of common salt and K2Cr2O7 in equal amount along with concentrated H2SO4 in a tJEE Mains Chemistry Past Papers Chemistry Question

Question

On heating a mixture of common salt and K2Cr2O7 in equal amount along with concentrated H2SO4 in a test tube, a gas is evolved. Formula of the gas evolved and oxidation state of the central metal atom in the gas respectively are : (A) CrO2Cl2 and +5 (B) CrO2Cl2 and +6 (C) Cr2O2Cl2 and +6 (D) Cr2O2Cl2 and +3

Answer: B

💡 Solution & Explanation

4NaCl + K2Cr2O7 + 6H2SO4  2KHSO4 + 2CrO2Cl2 + 4NaHSO4 + 3H2O (Chromyl chloride) In Chromyl chloride Cr is in +6 oxidation state. SECTION-B

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Mains Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry