For Freundlich adsorption isotherm, a plot of log (x/m) y(-axis) and log p (x-axis) gives a straight line. the intercept and slope for the line is 0.4771 and 2, respectively. The mass of gas, adsorbed

Question

For Freundlich adsorption isotherm, a plot of log (x/m) y(-axis) and log p (x-axis) gives a straight line. the intercept and slope for the line is 0.4771 and 2, respectively. The mass of gas, adsorbed per gram of adsorbent if the initial pressure is 0.04 atm is______×10–4g. (log 3 = 0.4771)

Prashant Kotian · Accepted Answer

Correct answer: .. .       m x = n ) P ( k       m x log = logk + P log n  Slope = n = 2 So n = . Intercept  logk = 0.477 So k = Antilog (0.477) = 3 So n ) P ( k m x        = 3[0.04]2 = 48 × 10–4 logP logk=0.477 Slope=2       m x log

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