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AITS & Test SerieshardMCQ SINGLE

Question

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Answer: A

💡 Solution & Explanation

2.5 g/g adsorbent / . l n x k P m  since, log k = 0.699, Hence , k = 5; Slope = 1 tan45 1 n   Thus, 5 0.5 / x g g m  adsorbent

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