Correct answer: C. 0 0 1 T  4 0 0 P T   0 4 0 1 P   and 0 4 256P 1 81   4 0 4 0 0 P 256P 81    

See image | AITS & Test Series — Chem-Mantra

AITS & Test SerieshardMCQ SINGLE

Question

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Answer: C

💡 Solution & Explanation

0 0 1 T  4 0 0 P T   0 4 0 1 P   and 0 4 256P 1 81   4 0 4 0 0 P 256P 81    

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