Assuming pure 2s and 2p orbitals of carbon are used in forming CH4 molecule, which of the following — Chemical Bonding Chemistry Question

💡 Solution & Explanation

Step 1: London dispersion forces are directly proportional to the molecular weight, atomic size, and polarizability of the molecule. Step 2: For the group 14 hydrides (CH4, SiH4, GeH4, SnH4), molecular weight and size increase down the group. Step 3: SnH4 is the largest and heaviest hydride in this series, giving it the highest polarizability and therefore the strongest London dispersion forces.