See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Radial node n 1     2 0 1    = 1 o 3/2 Zr/2a R o o 1 Z Zr for 2s 2 e a a 2 2                        At radial node o Zr 2 0 a   Hence, o Zr 2 a  Angular function for 1/2 1 s 4       