See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Work is done against constant pressure and thus irreversible. V = 4 lit P = 1 atm w = –1  4 lit-atm = - 1 × 4 × 101.3 = - 405.2 Joule E a w    E 750 405.2    E 344.80 J   AITS-FT-X (Paper-2)-PCM(Sol.)-JEE(Advanced)/19 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 9 Mathematics PART – III SECTION – A