See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

A – B.D.E. of alkyne is high B – Be2C + H2O  Be(OH)2 + CH4 C - HBr or Symmetrical HBr/Peroxide  Br Symmetrical alkene D - C C C C F alk KOH C C C C (Major product) AITS-FT-XI-PCM(Sol.)-JEE(Main)/2021 Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 9