See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Let the cylinder is slightly displaced from mean position. The total energy of the system when elongation in spring is x. E = 2 2 2 2 1 1 1 1 kx Mv MR 2 2 2 2           Differentiating the above expression, we get 2 2 dx dv 1 2v dv 2kx M2v MR 0 dt dt 2 dt R    2kx + (2M + M) dv dt =0 dv 2K x dt 3M       T = 3M 2 2k 