AITS & Test SerieshardNUMERICAL

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Question

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Answer: 00003.00

💡 Solution & Explanation

3 2 1 1 3 2 2 1 5 6 1 tan tan 6 12 7 4 4 x x I dx x x x x x                                       2 3 1 1 3 2 1 2 2 1 tan tan 2 1 2 x x dx x x                                    2 x t dx dt    1 2 1 1 3 2 1 1 tan tan 1 t t dt t t                             1 1 2 1 1 2 1 1 tan tan tan t t dt t                       1 1 2       3 I  

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